• chortle_tortle@mander.xyz
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    11 months ago

    Mathematicians will in one breath tell you they aren’t fractions, then in the next tell you dz/dx = dz/dy * dy/dx

  • benignintervention@lemmy.world
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    11 months ago

    I found math in physics to have this really fun duality of “these are rigorous rules that must be followed” and “if we make a set of edge case assumptions, we can fit the square peg in the round hole”

    Also I will always treat the derivative operator as a fraction

    • Billegh@lemmy.world
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      11 months ago

      I always chafed at that.

      “Here are these rigid rules you must use and follow.”

      “How did we get these rules?”

      “By ignoring others.”

  • Worx@lemmynsfw.com
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    11 months ago

    It’s not even a fraction, you can just cancel out the two "d"s

  • Avicenna@lemmy.world
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    11 months ago

    Look it is so simple, it just acts on an uncountably infinite dimensional vector space of differentiable functions.

    • gandalf_der_12te@discuss.tchncs.de
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      11 months ago

      fun fact: the vector space of differentiable functions (at least on compact domains) is actually of countable dimension.

      still infinite though

      • Avicenna@lemmy.world
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        11 months ago

        Doesn’t BCT imply that infinite dimensional Banach spaces cannot have a countable basis

        • gandalf_der_12te@discuss.tchncs.de
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          11 months ago

          Uhm, yeah, but there’s two different definitions of basis iirc. And i’m using the analytical definition here; you’re talking about the linear algebra definition.

          • Avicenna@lemmy.world
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            11 months ago

            So I call an infinite dimensional vector space of countable/uncountable dimensions if it has a countable and uncountable basis. What is the analytical definition? Or do you mean basis in the sense of topology?

            • gandalf_der_12te@discuss.tchncs.de
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              11 months ago

              Uhm, i remember there’s two definitions for basis.

              The basis in linear algebra says that you can compose every vector v as a finite sum v = sum over i from 1 to N of a_i * v_i, where a_i are arbitrary coefficients

              The basis in analysis says that you can compose every vector v as an infinite sum v = sum over i from 1 to infinity of a_i * v_i. So that makes a convergent series. It requires that a topology is defined on the vector space fist, so convergence becomes well-defined. We call such a vector space of countably infinite dimension if such a basis (v_1, v_2, …) exists that every vector v can be represented as a convergent series.

              • Avicenna@lemmy.world
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                11 months ago

                Ah that makes sense, regular definition of basis is not much of use in infinite dimension anyways as far as I recall. Wonder if differentiability is required for what you said since polynomials on compact domains (probably required for uniform convergence or sth) would also work for cont functions I think.

                • gandalf_der_12te@discuss.tchncs.de
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                  11 months ago

                  regular definition of basis is not much of use in infinite dimension anyways as far as I recall.

                  yeah, that’s exactly why we have an alternative definition for that :D

                  Wonder if differentiability is required for what you said since polynomials on compact domains (probably required for uniform convergence or sth) would also work for cont functions I think.

                  Differentiability is not required; what is required is a topology, i.e. a definition of convergence to make sure the infinite series are well-defined.

    • marcos@lemmy.world
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      11 months ago

      And it denotes an operation that gives you that fraction in operational algebra…

      Instead of making it clear that d is an operator, not a value, and thus the entire thing becomes an operator, physicists keep claiming that there’s no fraction involved. I guess they like confusing people.

  • Zerush@lemmy.ml
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    11 months ago

    When a mathematician want to scare an physicist he only need to speak about ∞

    • corvus@lemmy.ml
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      11 months ago

      When a physicist want to impress a mathematician he explains how he tames infinities with renormalization.

  • shapis@lemmy.ml
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    11 months ago

    This very nice Romanian lady that taught me complex plane calculus made sure to emphasize that e^j*theta was just a notation.

    Then proceeded to just use it as if it was actually eulers number to the j arg. And I still don’t understand why and under what cases I can’t just assume it’s the actual thing.

    • Frezik@lemmy.blahaj.zone
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      11 months ago

      Let’s face it: Calculus notation is a mess. We have three different ways to notate a derivative, and they all suck.

      • JackbyDev@programming.dev
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        11 months ago

        Calculus was the only class I failed in college. It was one of those massive 200 student classes. The teacher had a thick accent and hand writing that was difficult to read. Also, I remember her using phrases like “iff” that at the time I thought was her misspelling something only to later realize it was short hand for “if and only if”, so I can’t imagine how many other things just blew over my head.

        I retook it in a much smaller class and had a much better time.

    • jsomae@lemmy.ml
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      11 months ago

      e𝘪θ is not just notation. You can graph the entire function ex+𝘪θ across the whole complex domain and find that it matches up smoothly with both the version restricted to the real axis (ex) and the imaginary axis (e𝘪θ). The complete version is:

      ex+𝘪θ := ex(cos(θ) + 𝘪sin(θ))

      Various proofs of this can be found on wikipeda. Since these proofs just use basic calculus, this means we didn’t need to invent any new notation along the way.

      • shapis@lemmy.ml
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        11 months ago

        I’m aware of that identity. There’s a good chance I misunderstood what she said about it being just a notation.

        • jsomae@lemmy.ml
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          11 months ago

          It’s not simply notation, since you can prove the identity from base principles. An alien species would be able to discover this independently.

  • Caveman@lemmy.world
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    11 months ago

    The thing is that it’s legit a fraction and d/dx actually explains what’s going on under the hood. People interact with it as an operator because it’s mostly looking up common derivatives and using the properties.

    Take for example f(x) dx to mean "the sum (∫) of supersmall sections of x (dx) multiplied by the value of x at that point ( f(x) ). This is why there’s dx at the end of all integrals.

    The same way you can say that the slope at x is tiny f(x) divided by tiny x or d*f(x) / dx or more traditionally (d/dx) * f(x).

      • jsomae@lemmy.ml
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        11 months ago

        it’s legit a fraction, just the numerator and denominator aren’t numbers.

          • jsomae@lemmy.ml
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            11 months ago

            try this on – Yes 👎

            It’s a fraction of two infinitesimals. Infinitesimals aren’t numbers, however, they have their own algebra and can be manipulated algebraically. It so happens that a fraction of two infinitesimals behaves as a derivative.

            • Kogasa@programming.dev
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              11 months ago

              Ok, but no. Infinitesimal-based foundations for calculus aren’t standard and if you try to make this work with differential forms you’ll get a convoluted mess that is far less elegant than the actual definitions. It’s just not founded on actual math. It’s hard for me to argue this with you because it comes down to simply not knowing the definition of a basic concept or having the necessary context to understand why that definition is used instead of others…

              • jsomae@lemmy.ml
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                11 months ago

                Why would you assume I don’t have the context? I have a degree in math. I could be wrong about this, I’m open-minded. By all means, please explain how infinitesimals don’t have a consistent algebra.

                • Kogasa@programming.dev
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                  11 months ago
                  1. I also have a masters in math and completed all coursework for a PhD. Infinitesimals never came up because they’re not part of standard foundations for analysis. I’d be shocked if they were addressed in any formal capacity in your curriculum, because why would they be? It can be useful to think in terms of infinitesimals for intuition but you should know the difference between intuition and formalism.

                  2. I didn’t say “infinitesimals don’t have a consistent algebra.” I’m familiar with NSA and other systems admitting infinitesimal-like objects. I said they’re not standard. They aren’t.

                  3. If you want to use differential forms to define 1D calculus, rather than a NSA/infinitesimal approach, you’ll eventually realize some of your definitions are circular, since differential forms themselves are defined with an implicit understanding of basic calculus. You can get around this circular dependence but only by introducing new definitions that are ultimately less elegant than the standard limit-based ones.

  • corvus@lemmy.ml
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    11 months ago

    Chicken thinking: “Someone please explain this guy how we solve the Schroëdinger equation”