• burntbacon@discuss.tchncs.de
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      7 months ago

      Thado-mathocist. The real chad all along.

      It makes me wonder if somewhere out there in a multiverse, a community of lisping incels all collectively draw the chad wojak as as an aramaic looking dude.

    • bitcrafter@programming.dev
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      7 months ago

      Imagining your death. :P

      But seriously, it’s perfectly sensible when remember that i is just the mathematical representation of “left turn”, just like -1 is the mathematical representation of “go backwards”-- and as we know, two left turns sends you backwards. So think about this triangle in the following way:

      Imagine you are a snail, starting at the origin. Now imagine that you walk forward 1 step along the horizontal line. Then you turn 90° to the left to start walking along the vertical line, but then, because you need to walk i steps along this line you take another 90° turn to the left, which means that you are now walking backwards and you end up back at the origin. How far away from the origin are you? Zero steps.

  • Avicenna@lemmy.world
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    7 months ago

    operative?

    Also mathematicians use i for imaginary, engineers use j. The story does not add up. I have never seen a single mathematician use j for imaginary.

    • sartalon@lemmy.world
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      7 months ago

      As an EE, I used both. Def not a mathematician though. Fuck that, I just plug variables into programs now.

    • Unlearned9545@lemmy.world
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      7 months ago

      Engineer here: mostly use i, but have seen j used plenty. First time I saw j used was by a maths professor.

      • Avicenna@lemmy.world
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        7 months ago

        Interesting I never saw j from a maths person. Friends (from a decade ago!) in electronics eng dep said they use j because i was reserved for current. perhaps the latter depends on the department.

  • Phoenix3875@lemmy.world
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    7 months ago

    I think rather d/dx is the operator. You apply it to an expression to bind free occurrences of x in that expression. For example, dx²/dx is best understood as d/dx (x²). The notation would be clear if you implement calculus in a program.

      • ඞmir@lemmy.ml
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        7 months ago

        If you use exterior calculus notation, with d = exterior derivative, everything makes so much more sense

    • yetAnotherUser@discuss.tchncs.de
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      7 months ago

      I just think of the definition of a derivative.

      d is just an infinitesimally small delta. So dy/dx is literally just lim (∆ -> 0) ∆y/∆x. which is the same as lim (x_1 -> x_0) [f(x_0) - f(x_1)] / [x_0 - x_1].

      Note: -> 0 isn’t standard notation. But writing x -> 0 requires another step of thinking: y = f(x) therefore ∆y = ∆f(x) = f(x + ∆x) - f(x) so you only need x approaching zero. But I prefer thinking d = lim (∆ -> 0) ∆.

  • laserm@lemmy.world
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    7 months ago

    Why would a mathematician use j for imaginary numbers and why would engineer be mad at them?

    • cooligula@sh.itjust.works
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      7 months ago

      But the post says before the integral, so I understand what they did would be $dx \int f(x)$, which is disgusting

  • marcos@lemmy.world
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    7 months ago

    Hum… I don’t think the integral “operator” applies by multiplication.

    You can put the dx at the beginning of the integral, but not before it.

      • marcos@lemmy.world
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        7 months ago

        Nobody on your link is treating the integral “operator” as multiplicative.

        dx \int f(x) is blatantly different from \int f(x) dx

    • OrganicMustard@lemmy.world
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      7 months ago

      If you were using nonstandard analysis with dx an infinitesimal you could put it outside I guess. Maybe with differential forms too?

      • marcos@lemmy.world
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        7 months ago

        Switch it with a summation operator and see if it makes sense. The problem isn’t the operation by itself, but the fact that the operator implies an argument application, like a function.

        • OrganicMustard@lemmy.world
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          7 months ago

          In the case of dx as an infinitesimal it makes sense. You are making a sum of all the values of the function in the integral range and multiplying with a constant dx.

      • Kogasa@programming.dev
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        7 months ago

        In the context of differential forms, an integral expression isn’t complete without an integral symbol and a differential form to be integrated.

    • Jarix@lemmy.world
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      7 months ago

      Imagine a top that isn’t math brained, giving you so much more opportunities to troll before they find out…and then when they do learn something you have been trolling them…

      • djsoren19@lemmy.blahaj.zone
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        7 months ago

        No, in my experience people like that just end up trolling me because they have no frame of reference and don’t care about reality. You can’t troll somebody with math if they reject the idea of learning anything about or using math.

        • Jarix@lemmy.world
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          7 months ago

          I can see that.

          I did mean someone not learned already, not someone that doesn’t care to learn but I will concede the point now that you pointed out the flaws

          if you have more opportunities to troll, then that’s also more room for disappointment as well, I guess I was thinking in terms of intensity more than opportunities. Thanks